\(2x^2-6x=2x.x-2x.3=2x\left(x-3\right)\)

\(2x^2-6x=2x\left(x-3\right)\)

\(2x\left(x-3\right)\)

\(=2x\left(x-3\right)\)

\(2x^2-6x=2x\left(x-3\right)\)

\(=x\left(2x^2-x-6\right)\)

\(=x\left(2x^2-4x+3x-6\right)\)

\(=x\left[2x\left(x-2\right)+3\left(x-2\right)\right]\)

\(=x\left(x-2\right)\left(2x+3\right)\)

x(2x^2-x-6)

x(2x^2-4x+3x-6)

x[2x(x-2)+3(x-2)]

x(2x+3)(x-2)

\(=2x\left(x+3\right)\)

2x² - 2y² - 6x - 6x = 2(x² - y²) - 6(x + y) = 2(x - y)(x + y) -2.3.(x + y) = 2(x + y)[(x - y) - 3] = 2(x + y)(x - y - 3)    

\(\text{ 2x² + 6x - 8 }\)

\(2\left(x^2+3x-4\right)=2\left(x-1\right)\left(x+4\right)\)

SORY I'M IN GRADE 6

Thợ Đào Mỏ Panda, mày bị điên à, không biết còn trả lời làm cái quái gì

Đã có đáp án:

2x^4-6x^3+x^2+6x-3

=2x^2-6x^3-3x^2-2x^2-6x-3

=2x^2(x^2-1)-6x(x^2-1)+3(x^2-1)

=(x^2-1)(2x^2-6x+3)

a) x³-2x²-x+2

=x(x²-1)+2(-x²+1)

=x(x²-1)-2(x²-1)

=(x²-1)(x-2)

b)

x²+6x-y²+9

=x²+6x+9-y²

=(x+3)²-y²

^{=(x+3-y)(x+3+y)}

    \(2x^4+x^3-6x^2+x+2\) 

= \(2x^4+4x^3-3x^3-6x^2+x+2\)

= \(2x^3\left(x+2\right)-3x^2\left(x+2\right)+\left(x+2\right)\)

= \(\left(x+2\right)\left(2x^3-3x^2+1\right)\)

=\(\left(x+2\right)\left(2x^3-2x^2-x^2+1\right)\)

=\(\left(x+2\right)\left(2x^2\left(x-1\right)-\left(x+1\right)\left(x-1\right)\right)\)

=\(\left(x+2\right)\left(x-1\right)\left(2x^2-x-1\right)\)

= \(\left(x+2\right)\left(x-1\right)\left(2x^2-2x+x-1\right)\)

=\(\left(x+2\right)\left(x-1\right)\left(2x\left(x-1\right)+\left(x-1\right)\right)\)

=\(\left(x+2\right)\left(2x+1\right)\left(x-1\right)^2\)